What are the solutions to the equation n(x)=-2x^2 ?

The solutions to the equation n(x)=-2x^2 are x=0,x=-n/2

Find the zeros of n(x)=-2x^2

The zeros of n(x)=-2x^2 are x=0,x=-n/2

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n (x) = - 2 x^{2}

x = 0, x = - \frac{n}{2}

Solution steps

n (x) = - 2 x^{2}

Move

2 x^{2}

to the left side

n x + 2 x^{2} = 0

Factor

n x + 2 x^{2} : x (n + 2 x)

x (n + 2 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or n + 2 x = 0

Solve

n + 2 x = 0 : x = - \frac{n}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{n}{2}

2 x + x^{2} = - 13

6 x^{2} - 16 x - 6 = 0

10 x^{2} + 25 x = 15

- 3 x^{2} - 6 x - 5 = 0

5 x^{2} - 36 = 0

What are the solutions to the equation n(x)=-2x^2 ?
The solutions to the equation n(x)=-2x^2 are x=0,x=-n/2
Find the zeros of n(x)=-2x^2
The zeros of n(x)=-2x^2 are x=0,x=-n/2