What are the solutions to the equation 3x^2+5x-68=0 ?

The solutions to the equation 3x^2+5x-68=0 are x=4,x=-17/3

Find the zeros of 3x^2+5x-68=0

The zeros of 3x^2+5x-68=0 are x=4,x=-17/3

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3 x^{2} + 5 x - 68 = 0

x = 4, x = - \frac{17}{3}

Solution steps

3 x^{2} + 5 x - 68 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 68 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 68) = 29

x_{1, 2} = \frac{- 5 \pm 29}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 29}{2 \cdot 3}, x_{2} = \frac{- 5 - 29}{2 \cdot 3}

x = \frac{- 5 + 29}{2 \cdot 3} : 4

x = \frac{- 5 - 29}{2 \cdot 3} : - \frac{17}{3}

The solutions to the quadratic equation are:

x = 4, x = - \frac{17}{3}

(x - 2) (x - 5) = 6

x^{2} - 5 x + 6

- 4 x^{2} + 8 x - 3 = 0

(4 x - 5)^{2} = 25

b (b + 5) = 0

What are the solutions to the equation 3x^2+5x-68=0 ?
The solutions to the equation 3x^2+5x-68=0 are x=4,x=-17/3
Find the zeros of 3x^2+5x-68=0
The zeros of 3x^2+5x-68=0 are x=4,x=-17/3