What are the solutions to the equation s^2-4s+8=0 ?

The solutions to the equation s^2-4s+8=0 are s=2+2i,s=2-2i

Find the zeros of s^2-4s+8=0

The zeros of s^2-4s+8=0 are s=2+2i,s=2-2i

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s^{2} - 4 s + 8 = 0

s = 2 + 2 i, s = 2 - 2 i

Solution steps

s^{2} - 4 s + 8 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 8 : 4 i

s_{1, 2} = \frac{- ( - 4 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 4 ) + 4 i}{2 \cdot 1}, s_{2} = \frac{- ( - 4 ) - 4 i}{2 \cdot 1}

s = \frac{- ( - 4 ) + 4 i}{2 \cdot 1} : 2 + 2 i

s = \frac{- ( - 4 ) - 4 i}{2 \cdot 1} : 2 - 2 i

The solutions to the quadratic equation are:

s = 2 + 2 i, s = 2 - 2 i

x^{2} + 10 x = 56

x^{2} - 18 x + 9 = 0

x^{2} + 49 - 14 x + x^{2} = 25

c, x^{2} - x y + y^{2} = c^{2}

x - 2 + x (x - 6) = 4

What are the solutions to the equation s^2-4s+8=0 ?
The solutions to the equation s^2-4s+8=0 are s=2+2i,s=2-2i
Find the zeros of s^2-4s+8=0
The zeros of s^2-4s+8=0 are s=2+2i,s=2-2i