What are the solutions to the equation solvefor c,x^2-xy+y^2=c^2 ?

The solutions to the equation solvefor c,x^2-xy+y^2=c^2 are c=sqrt(x^2-xy+y^2),c=-sqrt(x^2-xy+y^2)

Find the zeros of solvefor c,x^2-xy+y^2=c^2

The zeros of solvefor c,x^2-xy+y^2=c^2 are c=sqrt(x^2-xy+y^2),c=-sqrt(x^2-xy+y^2)

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solve for

c, x^{2} - x y + y^{2} = c^{2}

c = x^{2} - x y + y^{2}, c = - x^{2} - x y + y^{2}

Solution steps

x^{2} - x y + y^{2} = c^{2}

Switch sides

c^{2} = x^{2} - x y + y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = x^{2} - x y + y^{2}, c = - x^{2} - x y + y^{2}

x - 2 + x (x - 6) = 4

1.2 r^{2} + 5.7 r = 2.3

x^{2} - 4 x + 4 = 75

4 x^{2} + 8 x - 32 = 0

9 x^{2} - 5 x - 7 = 0

What are the solutions to the equation solvefor c,x^2-xy+y^2=c^2 ?
The solutions to the equation solvefor c,x^2-xy+y^2=c^2 are c=sqrt(x^2-xy+y^2),c=-sqrt(x^2-xy+y^2)
Find the zeros of solvefor c,x^2-xy+y^2=c^2
The zeros of solvefor c,x^2-xy+y^2=c^2 are c=sqrt(x^2-xy+y^2),c=-sqrt(x^2-xy+y^2)