What are the solutions to the equation x^2-18x+9=0 ?

The solutions to the equation x^2-18x+9=0 are x=3(3+2sqrt(2)),x=3(3-2sqrt(2))

Find the zeros of x^2-18x+9=0

The zeros of x^2-18x+9=0 are x=3(3+2sqrt(2)),x=3(3-2sqrt(2))

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x^{2} - 18 x + 9 = 0

x = 3 (3 + 22), x = 3 (3 - 22)

Solution steps

x^{2} - 18 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 9 = 122

x_{1, 2} = \frac{- ( - 18 ) \pm 12 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 12 2}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 12 2}{2 \cdot 1}

x = \frac{- ( - 18 ) + 12 2}{2 \cdot 1} : 3 (3 + 22)

x = \frac{- ( - 18 ) - 12 2}{2 \cdot 1} : 3 (3 - 22)

The solutions to the quadratic equation are:

x = 3 (3 + 22), x = 3 (3 - 22)

x^{2} + 49 - 14 x + x^{2} = 25

c, x^{2} - x y + y^{2} = c^{2}

x - 2 + x (x - 6) = 4

1.2 r^{2} + 5.7 r = 2.3

x^{2} - 4 x + 4 = 75

What are the solutions to the equation x^2-18x+9=0 ?
The solutions to the equation x^2-18x+9=0 are x=3(3+2sqrt(2)),x=3(3-2sqrt(2))
Find the zeros of x^2-18x+9=0
The zeros of x^2-18x+9=0 are x=3(3+2sqrt(2)),x=3(3-2sqrt(2))