What are the solutions to the equation (x+5)(2x-1)=0 ?

The solutions to the equation (x+5)(2x-1)=0 are x=-5,x= 1/2

Find the zeros of (x+5)(2x-1)=0

The zeros of (x+5)(2x-1)=0 are x=-5,x= 1/2

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(x + 5) (2 x - 1) = 0

x = - 5, x = \frac{1}{2}

Solution steps

(x + 5) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or 2 x - 1 = 0

Solve

x + 5 = 0 : x = - 5

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = - 5, x = \frac{1}{2}

- t^{2} + 2 t + 3 = 0

2 x^{2} - 6 x = - 1

k^{2} + 1 = 0

m^{2} + 45 m + 600 = 0

x^{2} + 3 b x - 10 b^{2} = 0

What are the solutions to the equation (x+5)(2x-1)=0 ?
The solutions to the equation (x+5)(2x-1)=0 are x=-5,x= 1/2
Find the zeros of (x+5)(2x-1)=0
The zeros of (x+5)(2x-1)=0 are x=-5,x= 1/2