What are the solutions to the equation k^2+1=0 ?

The solutions to the equation k^2+1=0 are k=i,k=-i

Find the zeros of k^2+1=0

The zeros of k^2+1=0 are k=i,k=-i

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k^{2} + 1 = 0

k = i, k = - i

Solution steps

k^{2} + 1 = 0

Move

1

to the right side

k^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = - 1, k = - - 1

- 1 = i

- - 1 = - i

k = i, k = - i

m^{2} + 45 m + 600 = 0

x^{2} + 3 b x - 10 b^{2} = 0

x^{2} = 8^{2} + 1 0^{2}

3 (3 x - 2) = (x + 4) (x - 4)

x^{2} - 5 x - 19 = 0

What are the solutions to the equation k^2+1=0 ?
The solutions to the equation k^2+1=0 are k=i,k=-i
Find the zeros of k^2+1=0
The zeros of k^2+1=0 are k=i,k=-i