What are the solutions to the equation m^2+45m+600=0 ?

The solutions to the equation m^2+45m+600=0 are m=-45/2+i(5sqrt(15))/2 ,m=-45/2-i(5sqrt(15))/2

Find the zeros of m^2+45m+600=0

The zeros of m^2+45m+600=0 are m=-45/2+i(5sqrt(15))/2 ,m=-45/2-i(5sqrt(15))/2

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m^{2} + 45 m + 600 = 0

m = - \frac{45}{2} + i \frac{5 15}{2}, m = - \frac{45}{2} - i \frac{5 15}{2}

Solution steps

m^{2} + 45 m + 600 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 45 \pm 4 5 ^{2} - 4 \cdot 1 \cdot 600}{2 \cdot 1}

Simplify

4 5^{2} - 4 \cdot 1 \cdot 600 : 515 i

m_{1, 2} = \frac{- 45 \pm 5 15 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 45 + 5 15 i}{2 \cdot 1}, m_{2} = \frac{- 45 - 5 15 i}{2 \cdot 1}

m = \frac{- 45 + 5 15 i}{2 \cdot 1} : - \frac{45}{2} + i \frac{5 15}{2}

m = \frac{- 45 - 5 15 i}{2 \cdot 1} : - \frac{45}{2} - i \frac{5 15}{2}

The solutions to the quadratic equation are:

m = - \frac{45}{2} + i \frac{5 15}{2}, m = - \frac{45}{2} - i \frac{5 15}{2}

x^{2} + 3 b x - 10 b^{2} = 0

x^{2} = 8^{2} + 1 0^{2}

3 (3 x - 2) = (x + 4) (x - 4)

x^{2} - 5 x - 19 = 0

3 x^{2} - 72 = 6 x

What are the solutions to the equation m^2+45m+600=0 ?
The solutions to the equation m^2+45m+600=0 are m=-45/2+i(5sqrt(15))/2 ,m=-45/2-i(5sqrt(15))/2
Find the zeros of m^2+45m+600=0
The zeros of m^2+45m+600=0 are m=-45/2+i(5sqrt(15))/2 ,m=-45/2-i(5sqrt(15))/2