What are the solutions to the equation completesquare x^2-6x-4=0 ?

The solutions to the equation completesquare x^2-6x-4=0 are x=sqrt(13)+3,x=-sqrt(13)+3

Find the zeros of completesquare x^2-6x-4=0

The zeros of completesquare x^2-6x-4=0 are x=sqrt(13)+3,x=-sqrt(13)+3

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x^{2} - 6 x - 4 = 0

x = 13 + 3, x = - 13 + 3

Decimal Notation

x = 6.60555 \dots, x = - 0.60555 \dots

Solution steps

x^{2} - 6 x - 4 = 0

Move

4

to the right side

x^{2} - 6 x = 4

Rewrite in the form

(x + a)^{2} = b

(x - 3)^{2} = 13

For

the solutions are

f (x) = a, - a

Solve

x - 3 = 13 : x = 13 + 3

Solve

x - 3 = - 13 : x = - 13 + 3

The solutions to the quadratic equation are:

x = 13 + 3, x = - 13 + 3

a^{2} + 1 = 3 a - 1

3 + 9 r^{2} = 12

s^{2} + 7 s + 1 = 0

- 0.003 x^{2} + 0.2 x + 3 = 0

r^{2} + 12 = 0

What are the solutions to the equation completesquare x^2-6x-4=0 ?
The solutions to the equation completesquare x^2-6x-4=0 are x=sqrt(13)+3,x=-sqrt(13)+3
Find the zeros of completesquare x^2-6x-4=0
The zeros of completesquare x^2-6x-4=0 are x=sqrt(13)+3,x=-sqrt(13)+3