What are the solutions to the equation 3+9r^2=12 ?

The solutions to the equation 3+9r^2=12 are r=1,r=-1

Find the zeros of 3+9r^2=12

The zeros of 3+9r^2=12 are r=1,r=-1

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3 + 9 r^{2} = 12

r = 1, r = - 1

Solution steps

3 + 9 r^{2} = 12

Move

3

to the right side

9 r^{2} = 9

Divide both sides by

9

r^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 1, r = - 1

1 = 1

- 1 = - 1

r = 1, r = - 1

s^{2} + 7 s + 1 = 0

- 0.003 x^{2} + 0.2 x + 3 = 0

r^{2} + 12 = 0

5 x^{2} - 20 x = 60

x^{2} + 12 x - 6 = 5

What are the solutions to the equation 3+9r^2=12 ?
The solutions to the equation 3+9r^2=12 are r=1,r=-1
Find the zeros of 3+9r^2=12
The zeros of 3+9r^2=12 are r=1,r=-1