What are the solutions to the equation s^2+7s+1=0 ?

The solutions to the equation s^2+7s+1=0 are s=(-7+3sqrt(5))/2 ,s=(-7-3sqrt(5))/2

Find the zeros of s^2+7s+1=0

The zeros of s^2+7s+1=0 are s=(-7+3sqrt(5))/2 ,s=(-7-3sqrt(5))/2

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s^{2} + 7 s + 1 = 0

s = \frac{- 7 + 3 5}{2}, s = \frac{- 7 - 3 5}{2}

Decimal Notation

s = - 0.14589 \dots, s = - 6.85410 \dots

Solution steps

s^{2} + 7 s + 1 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 1 = 35

s_{1, 2} = \frac{- 7 \pm 3 5}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 7 + 3 5}{2 \cdot 1}, s_{2} = \frac{- 7 - 3 5}{2 \cdot 1}

s = \frac{- 7 + 3 5}{2 \cdot 1} : \frac{- 7 + 3 5}{2}

s = \frac{- 7 - 3 5}{2 \cdot 1} : \frac{- 7 - 3 5}{2}

The solutions to the quadratic equation are:

s = \frac{- 7 + 3 5}{2}, s = \frac{- 7 - 3 5}{2}

- 0.003 x^{2} + 0.2 x + 3 = 0

r^{2} + 12 = 0

5 x^{2} - 20 x = 60

x^{2} + 12 x - 6 = 5

x (6 + x) - 2 (x + 1) - 5 x = 4

What are the solutions to the equation s^2+7s+1=0 ?
The solutions to the equation s^2+7s+1=0 are s=(-7+3sqrt(5))/2 ,s=(-7-3sqrt(5))/2
Find the zeros of s^2+7s+1=0
The zeros of s^2+7s+1=0 are s=(-7+3sqrt(5))/2 ,s=(-7-3sqrt(5))/2