What are the solutions to the equation -0.003x^2+0.2x+3=0 ?

The solutions to the equation -0.003x^2+0.2x+3=0 are x=-(10(sqrt(190)-10))/3 ,x=(10(10+sqrt(190)))/3

Find the zeros of -0.003x^2+0.2x+3=0

The zeros of -0.003x^2+0.2x+3=0 are x=-(10(sqrt(190)-10))/3 ,x=(10(10+sqrt(190)))/3

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- 0.003 x^{2} + 0.2 x + 3 = 0

x = - \frac{10 ( 190 - 10 )}{3}, x = \frac{10 ( 10 + 190 )}{3}

Solution steps

- 0.003 x^{2} + 0.2 x + 3 = 0

Multiply both sides by

1000

- 3 x^{2} + 200 x + 3000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 200 \pm 20 0 ^{2} - 4 ( - 3 ) \cdot 3000}{2 ( - 3 )}

20 0^{2} - 4 (- 3) \cdot 3000 = 20190

x_{1, 2} = \frac{- 200 \pm 20 190}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 200 + 20 190}{2 ( - 3 )}, x_{2} = \frac{- 200 - 20 190}{2 ( - 3 )}

x = \frac{- 200 + 20 190}{2 ( - 3 )} : - \frac{10 ( 190 - 10 )}{3}

x = \frac{- 200 - 20 190}{2 ( - 3 )} : \frac{10 ( 10 + 190 )}{3}

The solutions to the quadratic equation are:

x = - \frac{10 ( 190 - 10 )}{3}, x = \frac{10 ( 10 + 190 )}{3}

r^{2} + 12 = 0

5 x^{2} - 20 x = 60

x^{2} + 12 x - 6 = 5

x (6 + x) - 2 (x + 1) - 5 x = 4

(x + 9)^{2} = 16

What are the solutions to the equation -0.003x^2+0.2x+3=0 ?
The solutions to the equation -0.003x^2+0.2x+3=0 are x=-(10(sqrt(190)-10))/3 ,x=(10(10+sqrt(190)))/3
Find the zeros of -0.003x^2+0.2x+3=0
The zeros of -0.003x^2+0.2x+3=0 are x=-(10(sqrt(190)-10))/3 ,x=(10(10+sqrt(190)))/3