What are the solutions to the equation x^2+(3a-2b)x-6ab=0 ?

The solutions to the equation x^2+(3a-2b)x-6ab=0 are x=2b,x=-3a

Find the zeros of x^2+(3a-2b)x-6ab=0

The zeros of x^2+(3a-2b)x-6ab=0 are x=2b,x=-3a

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x^{2} + (3 a - 2 b) x - 6 ab = 0

x = 2 b, x = - 3 a

Solution steps

x^{2} + (3 a - 2 b) x - 6 ab = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 3 a - 2 b ) \pm ( 3 a - 2 b ) ^{2} - 4 \cdot 1 \cdot ( - 6 ab )}{2 \cdot 1}

Simplify

(3 a - 2 b)^{2} - 4 \cdot 1 \cdot (- 6 ab) : 3 a + 2 b

x_{1, 2} = \frac{- ( 3 a - 2 b ) \pm ( 3 a + 2 b )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( 3 a - 2 b ) + 3 a + 2 b}{2 \cdot 1}, x_{2} = \frac{- ( 3 a - 2 b ) - ( 3 a + 2 b )}{2 \cdot 1}

x = \frac{- ( 3 a - 2 b ) + 3 a + 2 b}{2 \cdot 1} : 2 b

x = \frac{- ( 3 a - 2 b ) - ( 3 a + 2 b )}{2 \cdot 1} : - 3 a

The solutions to the quadratic equation are:

x = 2 b, x = - 3 a

120 x - 4.5 x^{2} = 0

5 x^{2} - 7 x = 3

5 x^{2} - 7 x = 6

x^{2} - 16 x + 29 = 0

x^{2} + 5 x + c

What are the solutions to the equation x^2+(3a-2b)x-6ab=0 ?
The solutions to the equation x^2+(3a-2b)x-6ab=0 are x=2b,x=-3a
Find the zeros of x^2+(3a-2b)x-6ab=0
The zeros of x^2+(3a-2b)x-6ab=0 are x=2b,x=-3a