What are the solutions to the equation 8^2=5^2+x^2 ?

The solutions to the equation 8^2=5^2+x^2 are x=sqrt(39),x=-sqrt(39)

Find the zeros of 8^2=5^2+x^2

The zeros of 8^2=5^2+x^2 are x=sqrt(39),x=-sqrt(39)

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8^{2} = 5^{2} + x^{2}

x = 39, x = - 39

Solution steps

8^{2} = 5^{2} + x^{2}

Switch sides

5^{2} + x^{2} = 8^{2}

Move

5^{2}

to the right side

x^{2} = 39

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 39, x = - 39

2 1^{2} + b^{2} = 2 9^{2}

- 2 x^{2} - 7 x + 15 = 0

x^{2} + 4 x + 17 = 8 - 2 x

x, x^{2} - 5 x + 4 = 0

0.75 x^{2} - 1.7 x + 0.5 = 0

What are the solutions to the equation 8^2=5^2+x^2 ?
The solutions to the equation 8^2=5^2+x^2 are x=sqrt(39),x=-sqrt(39)
Find the zeros of 8^2=5^2+x^2
The zeros of 8^2=5^2+x^2 are x=sqrt(39),x=-sqrt(39)