What are the solutions to the equation completesquare 2x^2+7x+6=0 ?

The solutions to the equation completesquare 2x^2+7x+6=0 are x=-3/2 ,x=-2

Find the zeros of completesquare 2x^2+7x+6=0

The zeros of completesquare 2x^2+7x+6=0 are x=-3/2 ,x=-2

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2 x^{2} + 7 x + 6 = 0

x = - \frac{3}{2}, x = - 2

Solution steps

2 x^{2} + 7 x + 6 = 0

Move

6

to the right side

2 x^{2} + 7 x = - 6

Divide both sides by

2

\frac{2 x ^{2} + 7 x}{2} = \frac{- 6}{2}

x^{2} + \frac{7 x}{2} = - 3

Rewrite in the form

(x + a)^{2} = b

(x + \frac{7}{4})^{2} = \frac{1}{16}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{7}{4} = \frac{1}{16} : x = - \frac{3}{2}

Solve

x + \frac{7}{4} = - \frac{1}{16} : x = - 2

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - 2

9 x^{2} - 25 x - 30 = 0

(x - 2) (x + 5) = 9 x + 10

2 x^{2} - 8 x - 17 = 0

- 7 x^{2} - 25 x + 12 = 0

3 m^{2} - 6 m + 6 = 0

What are the solutions to the equation completesquare 2x^2+7x+6=0 ?
The solutions to the equation completesquare 2x^2+7x+6=0 are x=-3/2 ,x=-2
Find the zeros of completesquare 2x^2+7x+6=0
The zeros of completesquare 2x^2+7x+6=0 are x=-3/2 ,x=-2