What are the solutions to the equation 2x^2-8x-17=0 ?

The solutions to the equation 2x^2-8x-17=0 are x=(4+5sqrt(2))/2 ,x=(4-5sqrt(2))/2

Find the zeros of 2x^2-8x-17=0

The zeros of 2x^2-8x-17=0 are x=(4+5sqrt(2))/2 ,x=(4-5sqrt(2))/2

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2 x^{2} - 8 x - 17 = 0

x = \frac{4 + 5 2}{2}, x = \frac{4 - 5 2}{2}

Decimal Notation

x = 5.53553 \dots, x = - 1.53553 \dots

Solution steps

2 x^{2} - 8 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 ( - 17 )}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 (- 17) = 102

x_{1, 2} = \frac{- ( - 8 ) \pm 10 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 10 2}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 10 2}{2 \cdot 2}

x = \frac{- ( - 8 ) + 10 2}{2 \cdot 2} : \frac{4 + 5 2}{2}

x = \frac{- ( - 8 ) - 10 2}{2 \cdot 2} : \frac{4 - 5 2}{2}

The solutions to the quadratic equation are:

x = \frac{4 + 5 2}{2}, x = \frac{4 - 5 2}{2}

- 7 x^{2} - 25 x + 12 = 0

3 m^{2} - 6 m + 6 = 0

X^{2} - X - 6 = 9

x^{2} - \frac{5}{6} x = \frac{25}{6}

4 x^{2} - 2 x + \frac{1}{4} = 0

What are the solutions to the equation 2x^2-8x-17=0 ?
The solutions to the equation 2x^2-8x-17=0 are x=(4+5sqrt(2))/2 ,x=(4-5sqrt(2))/2
Find the zeros of 2x^2-8x-17=0
The zeros of 2x^2-8x-17=0 are x=(4+5sqrt(2))/2 ,x=(4-5sqrt(2))/2