What are the solutions to the equation (x-2)(x+5)=9x+10 ?

The solutions to the equation (x-2)(x+5)=9x+10 are x=3+sqrt(29),x=3-sqrt(29)

Find the zeros of (x-2)(x+5)=9x+10

The zeros of (x-2)(x+5)=9x+10 are x=3+sqrt(29),x=3-sqrt(29)

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(x - 2) (x + 5) = 9 x + 10

x = 3 + 29, x = 3 - 29

Solution steps

(x - 2) (x + 5) = 9 x + 10

Expand

(x - 2) (x + 5) : x^{2} + 3 x - 10

x^{2} + 3 x - 10 = 9 x + 10

Move

10

to the left side

x^{2} + 3 x - 20 = 9 x

Move

9 x

to the left side

x^{2} - 6 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 20) = 229

x_{1, 2} = \frac{- ( - 6 ) \pm 2 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 29}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 29}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 29}{2 \cdot 1} : 3 + 29

x = \frac{- ( - 6 ) - 2 29}{2 \cdot 1} : 3 - 29

The solutions to the quadratic equation are:

x = 3 + 29, x = 3 - 29

2 x^{2} - 8 x - 17 = 0

- 7 x^{2} - 25 x + 12 = 0

3 m^{2} - 6 m + 6 = 0

X^{2} - X - 6 = 9

x^{2} - \frac{5}{6} x = \frac{25}{6}

What are the solutions to the equation (x-2)(x+5)=9x+10 ?
The solutions to the equation (x-2)(x+5)=9x+10 are x=3+sqrt(29),x=3-sqrt(29)
Find the zeros of (x-2)(x+5)=9x+10
The zeros of (x-2)(x+5)=9x+10 are x=3+sqrt(29),x=3-sqrt(29)