What are the solutions to the equation -7x^2-25x+12=0 ?

The solutions to the equation -7x^2-25x+12=0 are x=-4,x= 3/7

Find the zeros of -7x^2-25x+12=0

The zeros of -7x^2-25x+12=0 are x=-4,x= 3/7

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- 7 x^{2} - 25 x + 12 = 0

x = - 4, x = \frac{3}{7}

Decimal Notation

x = - 4, x = 0.42857 \dots

Solution steps

- 7 x^{2} - 25 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 ( - 7 ) \cdot 12}{2 ( - 7 )}

(- 25)^{2} - 4 (- 7) \cdot 12 = 31

x_{1, 2} = \frac{- ( - 25 ) \pm 31}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 31}{2 ( - 7 )}, x_{2} = \frac{- ( - 25 ) - 31}{2 ( - 7 )}

x = \frac{- ( - 25 ) + 31}{2 ( - 7 )} : - 4

x = \frac{- ( - 25 ) - 31}{2 ( - 7 )} : \frac{3}{7}

The solutions to the quadratic equation are:

x = - 4, x = \frac{3}{7}

3 m^{2} - 6 m + 6 = 0

X^{2} - X - 6 = 9

x^{2} - \frac{5}{6} x = \frac{25}{6}

4 x^{2} - 2 x + \frac{1}{4} = 0

(2 x - 1) (3 x + 4) = 0

What are the solutions to the equation -7x^2-25x+12=0 ?
The solutions to the equation -7x^2-25x+12=0 are x=-4,x= 3/7
Find the zeros of -7x^2-25x+12=0
The zeros of -7x^2-25x+12=0 are x=-4,x= 3/7