What are the solutions to the equation (2x-1)(3x+4)=0 ?

The solutions to the equation (2x-1)(3x+4)=0 are x= 1/2 ,x=-4/3

Find the zeros of (2x-1)(3x+4)=0

The zeros of (2x-1)(3x+4)=0 are x= 1/2 ,x=-4/3

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(2 x - 1) (3 x + 4) = 0

x = \frac{1}{2}, x = - \frac{4}{3}

Solution steps

(2 x - 1) (3 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or 3 x + 4 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{4}{3}

28 y + 4 = 3 y^{2}

4 x^{2} + 10 x - 13 = 5 x

6 x^{2} + 10 = 4 x

2 (x + 1)^{2} - 1 = 9

3 n - 6 = 18 n^{2}

What are the solutions to the equation (2x-1)(3x+4)=0 ?
The solutions to the equation (2x-1)(3x+4)=0 are x= 1/2 ,x=-4/3
Find the zeros of (2x-1)(3x+4)=0
The zeros of (2x-1)(3x+4)=0 are x= 1/2 ,x=-4/3