What are the solutions to the equation 4x^2+10x-13=5x ?

The solutions to the equation 4x^2+10x-13=5x are x=(-5+sqrt(233))/8 ,x=(-5-sqrt(233))/8

Find the zeros of 4x^2+10x-13=5x

The zeros of 4x^2+10x-13=5x are x=(-5+sqrt(233))/8 ,x=(-5-sqrt(233))/8

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4 x^{2} + 10 x - 13 = 5 x

x = \frac{- 5 + 233}{8}, x = \frac{- 5 - 233}{8}

Solution steps

4 x^{2} + 10 x - 13 = 5 x

Move

5 x

to the left side

4 x^{2} + 5 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 ( - 13 )}{2 \cdot 4}

5^{2} - 4 \cdot 4 (- 13) = 233

x_{1, 2} = \frac{- 5 \pm 233}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 233}{2 \cdot 4}, x_{2} = \frac{- 5 - 233}{2 \cdot 4}

x = \frac{- 5 + 233}{2 \cdot 4} : \frac{- 5 + 233}{8}

x = \frac{- 5 - 233}{2 \cdot 4} : \frac{- 5 - 233}{8}

The solutions to the quadratic equation are:

x = \frac{- 5 + 233}{8}, x = \frac{- 5 - 233}{8}

6 x^{2} + 10 = 4 x

2 (x + 1)^{2} - 1 = 9

3 n - 6 = 18 n^{2}

3^{2} = x^{2} + 1^{2}

x^{2} + 3 x (x - 12) = 0

What are the solutions to the equation 4x^2+10x-13=5x ?
The solutions to the equation 4x^2+10x-13=5x are x=(-5+sqrt(233))/8 ,x=(-5-sqrt(233))/8
Find the zeros of 4x^2+10x-13=5x
The zeros of 4x^2+10x-13=5x are x=(-5+sqrt(233))/8 ,x=(-5-sqrt(233))/8