What are the solutions to the equation 10^2+y^2=12^2 ?

The solutions to the equation 10^2+y^2=12^2 are y=2sqrt(11),y=-2sqrt(11)

Find the zeros of 10^2+y^2=12^2

The zeros of 10^2+y^2=12^2 are y=2sqrt(11),y=-2sqrt(11)

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1 0^{2} + y^{2} = 1 2^{2}

y = 211, y = - 211

Decimal Notation

y = 6.63324 \dots, y = - 6.63324 \dots

Solution steps

1 0^{2} + y^{2} = 1 2^{2}

Move

1 0^{2}

to the right side

y^{2} = 44

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 44, y = - 44

44 = 211

- 44 = - 211

y = 211, y = - 211

p^{2} + 8 p + 15 = 0

3 x^{2} - 8 x + 12 = 0

x^{2} = 6^{2} + 2^{2}

3 (x - 4)^{2} = 2 (x - 4)

z^{2} - 0.75 z + 0.125 = 0

What are the solutions to the equation 10^2+y^2=12^2 ?
The solutions to the equation 10^2+y^2=12^2 are y=2sqrt(11),y=-2sqrt(11)
Find the zeros of 10^2+y^2=12^2
The zeros of 10^2+y^2=12^2 are y=2sqrt(11),y=-2sqrt(11)