What are the solutions to the equation 3x^2-8x+12=0 ?

The solutions to the equation 3x^2-8x+12=0 are x= 4/3+i(2sqrt(5))/3 ,x= 4/3-i(2sqrt(5))/3

Find the zeros of 3x^2-8x+12=0

The zeros of 3x^2-8x+12=0 are x= 4/3+i(2sqrt(5))/3 ,x= 4/3-i(2sqrt(5))/3

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3 x^{2} - 8 x + 12 = 0

x = \frac{4}{3} + i \frac{2 5}{3}, x = \frac{4}{3} - i \frac{2 5}{3}

Solution steps

3 x^{2} - 8 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

Simplify

(- 8)^{2} - 4 \cdot 3 \cdot 12 : 45 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 5 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 5 i}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 4 5 i}{2 \cdot 3}

x = \frac{- ( - 8 ) + 4 5 i}{2 \cdot 3} : \frac{4}{3} + i \frac{2 5}{3}

x = \frac{- ( - 8 ) - 4 5 i}{2 \cdot 3} : \frac{4}{3} - i \frac{2 5}{3}

The solutions to the quadratic equation are:

x = \frac{4}{3} + i \frac{2 5}{3}, x = \frac{4}{3} - i \frac{2 5}{3}

x^{2} = 6^{2} + 2^{2}

3 (x - 4)^{2} = 2 (x - 4)

z^{2} - 0.75 z + 0.125 = 0

5 = (x - 3)^{2}

x^{2} = a^{2} + a^{2}

What are the solutions to the equation 3x^2-8x+12=0 ?
The solutions to the equation 3x^2-8x+12=0 are x= 4/3+i(2sqrt(5))/3 ,x= 4/3-i(2sqrt(5))/3
Find the zeros of 3x^2-8x+12=0
The zeros of 3x^2-8x+12=0 are x= 4/3+i(2sqrt(5))/3 ,x= 4/3-i(2sqrt(5))/3