What are the solutions to the equation 3x^2+x-7=0 ?

The solutions to the equation 3x^2+x-7=0 are x=(-1+sqrt(85))/6 ,x=(-1-sqrt(85))/6

Find the zeros of 3x^2+x-7=0

The zeros of 3x^2+x-7=0 are x=(-1+sqrt(85))/6 ,x=(-1-sqrt(85))/6

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3 x^{2} + x - 7 = 0

x = \frac{- 1 + 85}{6}, x = \frac{- 1 - 85}{6}

Decimal Notation

x = 1.36992 \dots, x = - 1.70325 \dots

Solution steps

3 x^{2} + x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 7) = 85

x_{1, 2} = \frac{- 1 \pm 85}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 85}{2 \cdot 3}, x_{2} = \frac{- 1 - 85}{2 \cdot 3}

x = \frac{- 1 + 85}{2 \cdot 3} : \frac{- 1 + 85}{6}

x = \frac{- 1 - 85}{2 \cdot 3} : \frac{- 1 - 85}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 85}{6}, x = \frac{- 1 - 85}{6}

m^{2} - 2 m - 5 = 0

3 x^{2} - 4 x = 5

x^{2} - 4 = 32

4 x (x - 3) = - 9

x^{2} - 4 = 12

What are the solutions to the equation 3x^2+x-7=0 ?
The solutions to the equation 3x^2+x-7=0 are x=(-1+sqrt(85))/6 ,x=(-1-sqrt(85))/6
Find the zeros of 3x^2+x-7=0
The zeros of 3x^2+x-7=0 are x=(-1+sqrt(85))/6 ,x=(-1-sqrt(85))/6