What are the solutions to the equation 4x^2+x+8=0 ?

The solutions to the equation 4x^2+x+8=0 are x=-1/8+i(sqrt(127))/8 ,x=-1/8-i(sqrt(127))/8

Find the zeros of 4x^2+x+8=0

The zeros of 4x^2+x+8=0 are x=-1/8+i(sqrt(127))/8 ,x=-1/8-i(sqrt(127))/8

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4 x^{2} + x + 8 = 0

x = - \frac{1}{8} + i \frac{127}{8}, x = - \frac{1}{8} - i \frac{127}{8}

Solution steps

4 x^{2} + x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 \cdot 8}{2 \cdot 4}

Simplify

1^{2} - 4 \cdot 4 \cdot 8 : 127 i

x_{1, 2} = \frac{- 1 \pm 127 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 1 + 127 i}{2 \cdot 4}, x_{2} = \frac{- 1 - 127 i}{2 \cdot 4}

x = \frac{- 1 + 127 i}{2 \cdot 4} : - \frac{1}{8} + i \frac{127}{8}

x = \frac{- 1 - 127 i}{2 \cdot 4} : - \frac{1}{8} - i \frac{127}{8}

The solutions to the quadratic equation are:

x = - \frac{1}{8} + i \frac{127}{8}, x = - \frac{1}{8} - i \frac{127}{8}

2 x^{2} + \frac{5}{2} x - \frac{3}{4} = 0

(x - 4) (x - 7) = 0

x, 1 - 2 x y + y^{2} = - x^{2} - 1 + 2 x y

3 x^{2} - 16 x + 23 = 0

3 x^{2} = 5 + 8 x

What are the solutions to the equation 4x^2+x+8=0 ?
The solutions to the equation 4x^2+x+8=0 are x=-1/8+i(sqrt(127))/8 ,x=-1/8-i(sqrt(127))/8
Find the zeros of 4x^2+x+8=0
The zeros of 4x^2+x+8=0 are x=-1/8+i(sqrt(127))/8 ,x=-1/8-i(sqrt(127))/8