What are the solutions to the equation m^2+8m+7=0 ?

The solutions to the equation m^2+8m+7=0 are m=-1,m=-7

Find the zeros of m^2+8m+7=0

The zeros of m^2+8m+7=0 are m=-1,m=-7

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m^{2} + 8 m + 7 = 0

m = - 1, m = - 7

Solution steps

m^{2} + 8 m + 7 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 7 = 6

m_{1, 2} = \frac{- 8 \pm 6}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 8 + 6}{2 \cdot 1}, m_{2} = \frac{- 8 - 6}{2 \cdot 1}

m = \frac{- 8 + 6}{2 \cdot 1} : - 1

m = \frac{- 8 - 6}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

m = - 1, m = - 7

4 x^{2} + x + 8 = 0

2 x^{2} + \frac{5}{2} x - \frac{3}{4} = 0

(x - 4) (x - 7) = 0

x, 1 - 2 x y + y^{2} = - x^{2} - 1 + 2 x y

3 x^{2} - 16 x + 23 = 0

What are the solutions to the equation m^2+8m+7=0 ?
The solutions to the equation m^2+8m+7=0 are m=-1,m=-7
Find the zeros of m^2+8m+7=0
The zeros of m^2+8m+7=0 are m=-1,m=-7