What are the solutions to the equation 21^2+28^2=x^2 ?

The solutions to the equation 21^2+28^2=x^2 are x=35,x=-35

Find the zeros of 21^2+28^2=x^2

The zeros of 21^2+28^2=x^2 are x=35,x=-35

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2 1^{2} + 2 8^{2} = x^{2}

x = 35, x = - 35

Solution steps

2 1^{2} + 2 8^{2} = x^{2}

Switch sides

x^{2} = 2 1^{2} + 2 8^{2}

Simplify

2 1^{2} + 2 8^{2} : 1225

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1225, x = - 1225

1225 = 35

- 1225 = - 35

x = 35, x = - 35

9 x^{2} + 6 x - 3 = 0

24 x^{2} + 48 x = 0

ab x^{2} - (b - 2 a) x - 2 = 0

x^{2} - 3 = 0

x, 36 x^{2} + 64 y^{2} + 360 x - 512 y + 1924 = 0

What are the solutions to the equation 21^2+28^2=x^2 ?
The solutions to the equation 21^2+28^2=x^2 are x=35,x=-35
Find the zeros of 21^2+28^2=x^2
The zeros of 21^2+28^2=x^2 are x=35,x=-35