What are the solutions to the equation x^2+ax+1=0 ?

The solutions to the equation x^2+ax+1=0 are x=(-a+sqrt(a^2-4))/2 ,x=(-a-sqrt(a^2-4))/2

Find the zeros of x^2+ax+1=0

The zeros of x^2+ax+1=0 are x=(-a+sqrt(a^2-4))/2 ,x=(-a-sqrt(a^2-4))/2

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x^{2} + a x + 1 = 0

x = \frac{- a + a ^{2} - 4}{2}, x = \frac{- a - a ^{2} - 4}{2}

Solution steps

x^{2} + a x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- a \pm a ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

Simplify

a^{2} - 4 \cdot 1 \cdot 1 : a^{2} - 4

x_{1, 2} = \frac{- a \pm a ^{2} - 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- a + a ^{2} - 4}{2 \cdot 1}, x_{2} = \frac{- a - a ^{2} - 4}{2 \cdot 1}

x = \frac{- a + a ^{2} - 4}{2 \cdot 1} : \frac{- a + a ^{2} - 4}{2}

x = \frac{- a - a ^{2} - 4}{2 \cdot 1} : \frac{- a - a ^{2} - 4}{2}

The solutions to the quadratic equation are:

x = \frac{- a + a ^{2} - 4}{2}, x = \frac{- a - a ^{2} - 4}{2}

(x + 1)^{2} = - 121

x^{2} + 21 x + 20 = 0

x^{2} + 11 x + 5 = 0

x, 7 x - y + 3 x y = x^{2} + y^{2}

(4 + x) (5 - 2 x) = (2 x + 1) (x - 2)

What are the solutions to the equation x^2+ax+1=0 ?
The solutions to the equation x^2+ax+1=0 are x=(-a+sqrt(a^2-4))/2 ,x=(-a-sqrt(a^2-4))/2
Find the zeros of x^2+ax+1=0
The zeros of x^2+ax+1=0 are x=(-a+sqrt(a^2-4))/2 ,x=(-a-sqrt(a^2-4))/2