What are the solutions to the equation x^2+38=16 ?

The solutions to the equation x^2+38=16 are x=sqrt(22)i,x=-sqrt(22)i

Find the zeros of x^2+38=16

The zeros of x^2+38=16 are x=sqrt(22)i,x=-sqrt(22)i

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x^{2} + 38 = 16

x = 22 i, x = - 22 i

Solution steps

x^{2} + 38 = 16

Move

38

to the right side

x^{2} = - 22

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 22, x = - - 22

- 22 = 22 i

- - 22 = - 22 i

x = 22 i, x = - 22 i

- 2 (3 x - 2)^{2} = - 200

- x^{2} + 6 x = x + 4

v^{2} + 2 v - 15 = 0

6 x^{2} + 2 x - 8 = 0

x^{2} - 81 = 0

What are the solutions to the equation x^2+38=16 ?
The solutions to the equation x^2+38=16 are x=sqrt(22)i,x=-sqrt(22)i
Find the zeros of x^2+38=16
The zeros of x^2+38=16 are x=sqrt(22)i,x=-sqrt(22)i