What are the solutions to the equation 4x^2=2-7x ?

The solutions to the equation 4x^2=2-7x are x= 1/4 ,x=-2

Find the zeros of 4x^2=2-7x

The zeros of 4x^2=2-7x are x= 1/4 ,x=-2

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4 x^{2} = 2 - 7 x

x = \frac{1}{4}, x = - 2

Decimal Notation

x = 0.25, x = - 2

Solution steps

4 x^{2} = 2 - 7 x

Move

7 x

to the left side

4 x^{2} + 7 x = 2

Move

2

to the left side

4 x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

7^{2} - 4 \cdot 4 (- 2) = 9

x_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 7 + 9}{2 \cdot 4}, x_{2} = \frac{- 7 - 9}{2 \cdot 4}

x = \frac{- 7 + 9}{2 \cdot 4} : \frac{1}{4}

x = \frac{- 7 - 9}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - 2

x^{2} + (x + 5)^{2} + 83 = 1200

x^{2} + 35 = - 12 x

t^{2} + 6 t + 5 = 0

z^{2} - 6 z

z^{2} + 8 z

What are the solutions to the equation 4x^2=2-7x ?
The solutions to the equation 4x^2=2-7x are x= 1/4 ,x=-2
Find the zeros of 4x^2=2-7x
The zeros of 4x^2=2-7x are x= 1/4 ,x=-2