What are the solutions to the equation solvefor p,q=150-p^2 ?

The solutions to the equation solvefor p,q=150-p^2 are p=sqrt(-q+150),p=-sqrt(-q+150)

Find the zeros of solvefor p,q=150-p^2

The zeros of solvefor p,q=150-p^2 are p=sqrt(-q+150),p=-sqrt(-q+150)

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solve for

p, q = 150 - p^{2}

p = - q + 150, p = - - q + 150

Solution steps

q = 150 - p^{2}

Switch sides

150 - p^{2} = q

Move

150

to the right side

- p^{2} = q - 150

Divide both sides by

- 1

p^{2} = - q + 150

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = - q + 150, p = - - q + 150

- t^{2} = t^{2}

x^{2} - 10 x = - 36

5 x^{2} + 4 x + 5 = 0

x, x^{2} + 10 x + 25 = 0

x, (x + 2)^{2} - (y + 5)^{2} = 0

What are the solutions to the equation solvefor p,q=150-p^2 ?
The solutions to the equation solvefor p,q=150-p^2 are p=sqrt(-q+150),p=-sqrt(-q+150)
Find the zeros of solvefor p,q=150-p^2
The zeros of solvefor p,q=150-p^2 are p=sqrt(-q+150),p=-sqrt(-q+150)