What are the solutions to the equation 0.3x^2-0.2x+0.25=0 ?

The solutions to the equation 0.3x^2-0.2x+0.25=0 are x= 1/3+i(sqrt(26))/6 ,x= 1/3-i(sqrt(26))/6

Find the zeros of 0.3x^2-0.2x+0.25=0

The zeros of 0.3x^2-0.2x+0.25=0 are x= 1/3+i(sqrt(26))/6 ,x= 1/3-i(sqrt(26))/6

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0.3 x^{2} - 0.2 x + 0.25 = 0

x = \frac{1}{3} + i \frac{26}{6}, x = \frac{1}{3} - i \frac{26}{6}

Solution steps

0.3 x^{2} - 0.2 x + 0.25 = 0

Multiply both sides by

100

30 x^{2} - 20 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 30 \cdot 25}{2 \cdot 30}

Simplify

(- 20)^{2} - 4 \cdot 30 \cdot 25 : 1026 i

x_{1, 2} = \frac{- ( - 20 ) \pm 10 26 i}{2 \cdot 30}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 10 26 i}{2 \cdot 30}, x_{2} = \frac{- ( - 20 ) - 10 26 i}{2 \cdot 30}

x = \frac{- ( - 20 ) + 10 26 i}{2 \cdot 30} : \frac{1}{3} + i \frac{26}{6}

x = \frac{- ( - 20 ) - 10 26 i}{2 \cdot 30} : \frac{1}{3} - i \frac{26}{6}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{26}{6}, x = \frac{1}{3} - i \frac{26}{6}

9 x^{2} + 10 = 91

b, A = \frac{1}{2} (b^{1} + b^{2}) h

2 (x - 4) (x - 4) - 18 = 0

X^{2} + 4 X - 6 = 0

y, x = 2 (y - 1)^{2} + 2

What are the solutions to the equation 0.3x^2-0.2x+0.25=0 ?
The solutions to the equation 0.3x^2-0.2x+0.25=0 are x= 1/3+i(sqrt(26))/6 ,x= 1/3-i(sqrt(26))/6
Find the zeros of 0.3x^2-0.2x+0.25=0
The zeros of 0.3x^2-0.2x+0.25=0 are x= 1/3+i(sqrt(26))/6 ,x= 1/3-i(sqrt(26))/6