What are the solutions to the equation -5x^2-4x-1=0 ?

The solutions to the equation -5x^2-4x-1=0 are x=-2/5-i 1/5 ,x=-2/5+i 1/5

Find the zeros of -5x^2-4x-1=0

The zeros of -5x^2-4x-1=0 are x=-2/5-i 1/5 ,x=-2/5+i 1/5

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- 5 x^{2} - 4 x - 1 = 0

x = - \frac{2}{5} - i \frac{1}{5}, x = - \frac{2}{5} + i \frac{1}{5}

Solution steps

- 5 x^{2} - 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 5 ) ( - 1 )}{2 ( - 5 )}

Simplify

(- 4)^{2} - 4 (- 5) (- 1) : 2 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 i}{2 ( - 5 )}, x_{2} = \frac{- ( - 4 ) - 2 i}{2 ( - 5 )}

x = \frac{- ( - 4 ) + 2 i}{2 ( - 5 )} : - \frac{2}{5} - i \frac{1}{5}

x = \frac{- ( - 4 ) - 2 i}{2 ( - 5 )} : - \frac{2}{5} + i \frac{1}{5}

The solutions to the quadratic equation are:

x = - \frac{2}{5} - i \frac{1}{5}, x = - \frac{2}{5} + i \frac{1}{5}

4 x^{2} + 3 x - 22 = 0

- 14 x + 168 - 7 x^{2} = 0

x^{2} - 25 = (a + b) (a - c)

- 2 x^{2} + 12 x - 20 = 0

2 x^{2} - 15 = 65

What are the solutions to the equation -5x^2-4x-1=0 ?
The solutions to the equation -5x^2-4x-1=0 are x=-2/5-i 1/5 ,x=-2/5+i 1/5
Find the zeros of -5x^2-4x-1=0
The zeros of -5x^2-4x-1=0 are x=-2/5-i 1/5 ,x=-2/5+i 1/5