What are the solutions to the equation -2+x(x+5)=4 ?

The solutions to the equation -2+x(x+5)=4 are x=1,x=-6

Find the zeros of -2+x(x+5)=4

The zeros of -2+x(x+5)=4 are x=1,x=-6

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- 2 + x (x + 5) = 4

x = 1, x = - 6

Solution steps

- 2 + x (x + 5) = 4

Expand

- 2 + x (x + 5) : - 2 + x^{2} + 5 x

- 2 + x^{2} + 5 x = 4

Move

4

to the left side

x^{2} + 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 6) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 1}, x_{2} = \frac{- 5 - 7}{2 \cdot 1}

x = \frac{- 5 + 7}{2 \cdot 1} : 1

x = \frac{- 5 - 7}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 1, x = - 6

- x^{2} + 10 = 0

0 = - t^{2} + 3 t + 27

x^{2} + 28 x = 23.04

x^{2} + x - 21 = 0

(2 x + 5) (3 x - 2) = 4

What are the solutions to the equation -2+x(x+5)=4 ?
The solutions to the equation -2+x(x+5)=4 are x=1,x=-6
Find the zeros of -2+x(x+5)=4
The zeros of -2+x(x+5)=4 are x=1,x=-6