What are the solutions to the equation -x^2+10=0 ?

The solutions to the equation -x^2+10=0 are x=sqrt(10),x=-sqrt(10)

Find the zeros of -x^2+10=0

The zeros of -x^2+10=0 are x=sqrt(10),x=-sqrt(10)

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- x^{2} + 10 = 0

x = 10, x = - 10

Decimal Notation

x = 3.16227 \dots, x = - 3.16227 \dots

Solution steps

- x^{2} + 10 = 0

Move

10

to the right side

- x^{2} = - 10

Divide both sides by

- 1

x^{2} = 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 10, x = - 10

0 = - t^{2} + 3 t + 27

x^{2} + 28 x = 23.04

x^{2} + x - 21 = 0

(2 x + 5) (3 x - 2) = 4

- x^{2} - 7 x = 6

What are the solutions to the equation -x^2+10=0 ?
The solutions to the equation -x^2+10=0 are x=sqrt(10),x=-sqrt(10)
Find the zeros of -x^2+10=0
The zeros of -x^2+10=0 are x=sqrt(10),x=-sqrt(10)