What are the solutions to the equation 2x^2-19=-1 ?

The solutions to the equation 2x^2-19=-1 are x=3,x=-3

Find the zeros of 2x^2-19=-1

The zeros of 2x^2-19=-1 are x=3,x=-3

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2 x^{2} - 19 = - 1

x = 3, x = - 3

Solution steps

2 x^{2} - 19 = - 1

Move

19

to the right side

2 x^{2} = 18

Divide both sides by

2

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

u^{2} + 20 u = 0

x^{2} - 3 x + 7 = x + 52

5 - 4 x - x^{2}

4 x (x - 3) - (x - 1) (x + 3) = 2 (x - 3)^{2}

s^{2} + 3 s + 3 = 0

What are the solutions to the equation 2x^2-19=-1 ?
The solutions to the equation 2x^2-19=-1 are x=3,x=-3
Find the zeros of 2x^2-19=-1
The zeros of 2x^2-19=-1 are x=3,x=-3