What are the solutions to the equation u^2+20u=0 ?

The solutions to the equation u^2+20u=0 are u=0,u=-20

Find the zeros of u^2+20u=0

The zeros of u^2+20u=0 are u=0,u=-20

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u^{2} + 20 u = 0

u = 0, u = - 20

Solution steps

u^{2} + 20 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 0 = 20

u_{1, 2} = \frac{- 20 \pm 20}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 20 + 20}{2 \cdot 1}, u_{2} = \frac{- 20 - 20}{2 \cdot 1}

u = \frac{- 20 + 20}{2 \cdot 1} : 0

u = \frac{- 20 - 20}{2 \cdot 1} : - 20

The solutions to the quadratic equation are:

u = 0, u = - 20

x^{2} - 3 x + 7 = x + 52

5 - 4 x - x^{2}

4 x (x - 3) - (x - 1) (x + 3) = 2 (x - 3)^{2}

s^{2} + 3 s + 3 = 0

4 x^{2} + 31 x + 21 = 0

What are the solutions to the equation u^2+20u=0 ?
The solutions to the equation u^2+20u=0 are u=0,u=-20
Find the zeros of u^2+20u=0
The zeros of u^2+20u=0 are u=0,u=-20