What are the solutions to the equation 3x^2+24x+15=0 ?

The solutions to the equation 3x^2+24x+15=0 are x=-4+sqrt(11),x=-4-sqrt(11)

Find the zeros of 3x^2+24x+15=0

The zeros of 3x^2+24x+15=0 are x=-4+sqrt(11),x=-4-sqrt(11)

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3 x^{2} + 24 x + 15 = 0

x = - 4 + 11, x = - 4 - 11

Decimal Notation

x = - 0.68337 \dots, x = - 7.31662 \dots

Solution steps

3 x^{2} + 24 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 15}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 15 = 611

x_{1, 2} = \frac{- 24 \pm 6 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 24 + 6 11}{2 \cdot 3}, x_{2} = \frac{- 24 - 6 11}{2 \cdot 3}

x = \frac{- 24 + 6 11}{2 \cdot 3} : - 4 + 11

x = \frac{- 24 - 6 11}{2 \cdot 3} : - 4 - 11

The solutions to the quadratic equation are:

x = - 4 + 11, x = - 4 - 11

x, x^{2} + y^{2} + z^{2} - 2 y + 2 z - 2 = 0

(2 x - 3)^{2} = 6

(x + 2)^{2} = 3 x + 7

(x - 3) (x - 2) = 20

6 - 7 x = 3 x^{2}

What are the solutions to the equation 3x^2+24x+15=0 ?
The solutions to the equation 3x^2+24x+15=0 are x=-4+sqrt(11),x=-4-sqrt(11)
Find the zeros of 3x^2+24x+15=0
The zeros of 3x^2+24x+15=0 are x=-4+sqrt(11),x=-4-sqrt(11)