What are the solutions to the equation x^2+29x+100=0 ?

The solutions to the equation x^2+29x+100=0 are x=-4,x=-25

Find the zeros of x^2+29x+100=0

The zeros of x^2+29x+100=0 are x=-4,x=-25

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x^{2} + 29 x + 100 = 0

x = - 4, x = - 25

Solution steps

x^{2} + 29 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 29 \pm 2 9 ^{2} - 4 \cdot 1 \cdot 100}{2 \cdot 1}

2 9^{2} - 4 \cdot 1 \cdot 100 = 21

x_{1, 2} = \frac{- 29 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 29 + 21}{2 \cdot 1}, x_{2} = \frac{- 29 - 21}{2 \cdot 1}

x = \frac{- 29 + 21}{2 \cdot 1} : - 4

x = \frac{- 29 - 21}{2 \cdot 1} : - 25

The solutions to the quadratic equation are:

x = - 4, x = - 25

x, x^{2} - 7 x + 12 = 0

36 - 25 x^{2} = 0

x (x + 2) = 143

9 x^{2} + 24 x + 19 = 0

4 x^{2} + 10 x - 3 = 0

What are the solutions to the equation x^2+29x+100=0 ?
The solutions to the equation x^2+29x+100=0 are x=-4,x=-25
Find the zeros of x^2+29x+100=0
The zeros of x^2+29x+100=0 are x=-4,x=-25