What are the solutions to the equation -3x^2-2x-2=0 ?

The solutions to the equation -3x^2-2x-2=0 are x=-1/3-i(sqrt(5))/3 ,x=-1/3+i(sqrt(5))/3

Find the zeros of -3x^2-2x-2=0

The zeros of -3x^2-2x-2=0 are x=-1/3-i(sqrt(5))/3 ,x=-1/3+i(sqrt(5))/3

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- 3 x^{2} - 2 x - 2 = 0

x = - \frac{1}{3} - i \frac{5}{3}, x = - \frac{1}{3} + i \frac{5}{3}

Solution steps

- 3 x^{2} - 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 3 ) ( - 2 )}{2 ( - 3 )}

Simplify

(- 2)^{2} - 4 (- 3) (- 2) : 25 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 5 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 5 i}{2 ( - 3 )}, x_{2} = \frac{- ( - 2 ) - 2 5 i}{2 ( - 3 )}

x = \frac{- ( - 2 ) + 2 5 i}{2 ( - 3 )} : - \frac{1}{3} - i \frac{5}{3}

x = \frac{- ( - 2 ) - 2 5 i}{2 ( - 3 )} : - \frac{1}{3} + i \frac{5}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} - i \frac{5}{3}, x = - \frac{1}{3} + i \frac{5}{3}

x^{2} + 34 x = 0

(1 - x) (- 3 - x) + 5 = 0

x, 9 x^{2} - 4 y^{2} + 18 x - 16 y = 7

4 x^{2} + 34 x - 25 = 0

49 x^{2} - 7 x - \frac{3}{4}

What are the solutions to the equation -3x^2-2x-2=0 ?
The solutions to the equation -3x^2-2x-2=0 are x=-1/3-i(sqrt(5))/3 ,x=-1/3+i(sqrt(5))/3
Find the zeros of -3x^2-2x-2=0
The zeros of -3x^2-2x-2=0 are x=-1/3-i(sqrt(5))/3 ,x=-1/3+i(sqrt(5))/3