What are the solutions to the equation 0=x^2-8x+17 ?

The solutions to the equation 0=x^2-8x+17 are x=4+i,x=4-i

Find the zeros of 0=x^2-8x+17

The zeros of 0=x^2-8x+17 are x=4+i,x=4-i

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0 = x^{2} - 8 x + 17

x = 4 + i, x = 4 - i

Solution steps

0 = x^{2} - 8 x + 17

Switch sides

x^{2} - 8 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 17 : 2 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 i}{2 \cdot 1} : 4 + i

x = \frac{- ( - 8 ) - 2 i}{2 \cdot 1} : 4 - i

The solutions to the quadratic equation are:

x = 4 + i, x = 4 - i

x^{2} - 14 x + 49 = 12

- 4 x^{2} + 12 x + 9 = 0

- 2 x^{2} + 4 x + 30 = 0

x^{2} + 2 x^{2} - x - 2 = 0

2 x^{2} + 2 x - x - 1 = 0

What are the solutions to the equation 0=x^2-8x+17 ?
The solutions to the equation 0=x^2-8x+17 are x=4+i,x=4-i
Find the zeros of 0=x^2-8x+17
The zeros of 0=x^2-8x+17 are x=4+i,x=4-i