What are the solutions to the equation -x^2-10x+2000=0 ?

The solutions to the equation -x^2-10x+2000=0 are x=-50,x=40

Find the zeros of -x^2-10x+2000=0

The zeros of -x^2-10x+2000=0 are x=-50,x=40

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- x^{2} - 10 x + 2000 = 0

x = - 50, x = 40

Solution steps

- x^{2} - 10 x + 2000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 1 ) \cdot 2000}{2 ( - 1 )}

(- 10)^{2} - 4 (- 1) \cdot 2000 = 90

x_{1, 2} = \frac{- ( - 10 ) \pm 90}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 90}{2 ( - 1 )}, x_{2} = \frac{- ( - 10 ) - 90}{2 ( - 1 )}

x = \frac{- ( - 10 ) + 90}{2 ( - 1 )} : - 50

x = \frac{- ( - 10 ) - 90}{2 ( - 1 )} : 40

The solutions to the quadratic equation are:

x = - 50, x = 40

x, 15 x^{2} - 4 y^{2} + 15 z^{2} = - 4

x^{2} + 2 x = \frac{1}{4}

6 x^{2} + 9 x - 27 = 0

X^{2} + 2 X + 2 = 0

x^{2} + 7 x + 10 = 0

What are the solutions to the equation -x^2-10x+2000=0 ?
The solutions to the equation -x^2-10x+2000=0 are x=-50,x=40
Find the zeros of -x^2-10x+2000=0
The zeros of -x^2-10x+2000=0 are x=-50,x=40