What are the solutions to the equation 8/3 =4-x^2 ?

The solutions to the equation 8/3 =4-x^2 are x= 2/(sqrt(3)),x=-2/(sqrt(3))

Find the zeros of 8/3 =4-x^2

The zeros of 8/3 =4-x^2 are x= 2/(sqrt(3)),x=-2/(sqrt(3))

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\frac{8}{3} = 4 - x^{2}

x = \frac{2}{3}, x = - \frac{2}{3}

Decimal Notation

x = 1.15470 \dots, x = - 1.15470 \dots

Solution steps

\frac{8}{3} = 4 - x^{2}

Switch sides

4 - x^{2} = \frac{8}{3}

Move

4

to the right side

- x^{2} = \frac{8}{3} - 4

Simplify

\frac{8}{3} - 4 : - \frac{4}{3}

- x^{2} = - \frac{4}{3}

Divide both sides by

- 1

x^{2} = \frac{4}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{3}, x = - \frac{4}{3}

\frac{4}{3} = \frac{2}{3}

- \frac{4}{3} = - \frac{2}{3}

x = \frac{2}{3}, x = - \frac{2}{3}

(x - 2) 2 + x (x + 1) = 24

x^{2} + 8 x - 32 = 0

z, x^{3} z^{2} - 5 x y^{5} z = x^{2} + y^{3}

5 x^{2} - x + 6 = 5 - 7 x - 4 x^{2}

y, (x - 2)^{2} + (y + 3)^{2} = 4

What are the solutions to the equation 8/3 =4-x^2 ?
The solutions to the equation 8/3 =4-x^2 are x= 2/(sqrt(3)),x=-2/(sqrt(3))
Find the zeros of 8/3 =4-x^2
The zeros of 8/3 =4-x^2 are x= 2/(sqrt(3)),x=-2/(sqrt(3))