What are the solutions to the equation x^2+13x-10=0 ?

The solutions to the equation x^2+13x-10=0 are x=(-13+sqrt(209))/2 ,x=(-13-sqrt(209))/2

Find the zeros of x^2+13x-10=0

The zeros of x^2+13x-10=0 are x=(-13+sqrt(209))/2 ,x=(-13-sqrt(209))/2

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x^{2} + 13 x - 10 = 0

x = \frac{- 13 + 209}{2}, x = \frac{- 13 - 209}{2}

Decimal Notation

x = 0.72841 \dots, x = - 13.72841 \dots

Solution steps

x^{2} + 13 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot (- 10) = 209

x_{1, 2} = \frac{- 13 \pm 209}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 209}{2 \cdot 1}, x_{2} = \frac{- 13 - 209}{2 \cdot 1}

x = \frac{- 13 + 209}{2 \cdot 1} : \frac{- 13 + 209}{2}

x = \frac{- 13 - 209}{2 \cdot 1} : \frac{- 13 - 209}{2}

The solutions to the quadratic equation are:

x = \frac{- 13 + 209}{2}, x = \frac{- 13 - 209}{2}

x, f = x^{2} y^{2} z^{2}

(\frac{3}{5})^{2} + x^{2} = 1

x (x + 3) = 54

12 b^{2} - 27 = 0

x (x + 3) = - 2

What are the solutions to the equation x^2+13x-10=0 ?
The solutions to the equation x^2+13x-10=0 are x=(-13+sqrt(209))/2 ,x=(-13-sqrt(209))/2
Find the zeros of x^2+13x-10=0
The zeros of x^2+13x-10=0 are x=(-13+sqrt(209))/2 ,x=(-13-sqrt(209))/2