What are the solutions to the equation 6q^2-150q+600=0 ?

The solutions to the equation 6q^2-150q+600=0 are q=20,q=5

Find the zeros of 6q^2-150q+600=0

The zeros of 6q^2-150q+600=0 are q=20,q=5

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6 q^{2} - 150 q + 600 = 0

q = 20, q = 5

Solution steps

6 q^{2} - 150 q + 600 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 150 ) \pm ( - 150 ) ^{2} - 4 \cdot 6 \cdot 600}{2 \cdot 6}

(- 150)^{2} - 4 \cdot 6 \cdot 600 = 90

q_{1, 2} = \frac{- ( - 150 ) \pm 90}{2 \cdot 6}

Separate the solutions

q_{1} = \frac{- ( - 150 ) + 90}{2 \cdot 6}, q_{2} = \frac{- ( - 150 ) - 90}{2 \cdot 6}

q = \frac{- ( - 150 ) + 90}{2 \cdot 6} : 20

q = \frac{- ( - 150 ) - 90}{2 \cdot 6} : 5

The solutions to the quadratic equation are:

q = 20, q = 5

x, x^{2} - 14 x + 49 = 0

8 + 2 m^{2} = 32

t^{2} - 8 t = 0

13 - 6 x = (2 x - 5)^{2} + 3

x, - \frac{1}{y} = x - 4 x^{2}

What are the solutions to the equation 6q^2-150q+600=0 ?
The solutions to the equation 6q^2-150q+600=0 are q=20,q=5
Find the zeros of 6q^2-150q+600=0
The zeros of 6q^2-150q+600=0 are q=20,q=5