What are the solutions to the equation (x+3)^2+10^2=26^2 ?

The solutions to the equation (x+3)^2+10^2=26^2 are x=21,x=-27

Find the zeros of (x+3)^2+10^2=26^2

The zeros of (x+3)^2+10^2=26^2 are x=21,x=-27

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(x + 3)^{2} + 1 0^{2} = 2 6^{2}

x = 21, x = - 27

Solution steps

(x + 3)^{2} + 1 0^{2} = 2 6^{2}

Move

1 0^{2}

to the right side

(x + 3)^{2} = 576

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 576 : x = 21

Solve

x + 3 = - 576 : x = - 27

The solutions to the quadratic equation are:

x = 21, x = - 27

6 q^{2} - 150 q + 600 = 0

x, x^{2} - 14 x + 49 = 0

8 + 2 m^{2} = 32

t^{2} - 8 t = 0

13 - 6 x = (2 x - 5)^{2} + 3

What are the solutions to the equation (x+3)^2+10^2=26^2 ?
The solutions to the equation (x+3)^2+10^2=26^2 are x=21,x=-27
Find the zeros of (x+3)^2+10^2=26^2
The zeros of (x+3)^2+10^2=26^2 are x=21,x=-27