What are the solutions to the equation x^2+10=-6x ?

The solutions to the equation x^2+10=-6x are x=-3+i,x=-3-i

Find the zeros of x^2+10=-6x

The zeros of x^2+10=-6x are x=-3+i,x=-3-i

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x^{2} + 10 = - 6 x

x = - 3 + i, x = - 3 - i

Solution steps

x^{2} + 10 = - 6 x

Move

6 x

to the left side

x^{2} + 10 + 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 6 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 10 : 2 i

x_{1, 2} = \frac{- 6 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 i}{2 \cdot 1}

x = \frac{- 6 + 2 i}{2 \cdot 1} : - 3 + i

x = \frac{- 6 - 2 i}{2 \cdot 1} : - 3 - i

The solutions to the quadratic equation are:

x = - 3 + i, x = - 3 - i

12 x^{2} + 13 x = 5 x

(2 x + 2) (x) = 60

4 x^{2} + 24 x + 13 = 2 x^{2} + 6 x

x^{2} + 8 x - 35 = 0

x^{2} + 15 x + 64 = 0

What are the solutions to the equation x^2+10=-6x ?
The solutions to the equation x^2+10=-6x are x=-3+i,x=-3-i
Find the zeros of x^2+10=-6x
The zeros of x^2+10=-6x are x=-3+i,x=-3-i