What are the solutions to the equation 0=(x-3)^2+1 ?

The solutions to the equation 0=(x-3)^2+1 are x=i+3,x=-i+3

Find the zeros of 0=(x-3)^2+1

The zeros of 0=(x-3)^2+1 are x=i+3,x=-i+3

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0 = (x - 3)^{2} + 1

x = i + 3, x = - i + 3

Solution steps

0 = (x - 3)^{2} + 1

Switch sides

(x - 3)^{2} + 1 = 0

Move

1

to the right side

(x - 3)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = - 1 : x = i + 3

Solve

x - 3 = - - 1 : x = - i + 3

The solutions to the quadratic equation are:

x = i + 3, x = - i + 3

x, z = 4 - x^{2} - 2 y^{2}

x, x^{2} + m x + 7 = 0

5 b^{2} + 4 b + 4 = 0

\frac{1}{16} x^{2} + x + 4 = 0

x^{2} + 28 x

What are the solutions to the equation 0=(x-3)^2+1 ?
The solutions to the equation 0=(x-3)^2+1 are x=i+3,x=-i+3
Find the zeros of 0=(x-3)^2+1
The zeros of 0=(x-3)^2+1 are x=i+3,x=-i+3