What are the solutions to the equation x^2+16=4 ?

The solutions to the equation x^2+16=4 are x=2sqrt(3)i,x=-2sqrt(3)i

Find the zeros of x^2+16=4

The zeros of x^2+16=4 are x=2sqrt(3)i,x=-2sqrt(3)i

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x^{2} + 16 = 4

x = 23 i, x = - 23 i

Solution steps

x^{2} + 16 = 4

Move

16

to the right side

x^{2} = - 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 12, x = - - 12

- 12 = 23 i

- - 12 = - 23 i

x = 23 i, x = - 23 i

x^{2} + 7 x - 5 = 0

(x - 1) (x - 3) = 5

4 n^{2} + 1 = 157

y, 10 x^{2} - 3 y^{2} = 10

119.286 - 20 x + 7.5 x^{2} = 0

What are the solutions to the equation x^2+16=4 ?
The solutions to the equation x^2+16=4 are x=2sqrt(3)i,x=-2sqrt(3)i
Find the zeros of x^2+16=4
The zeros of x^2+16=4 are x=2sqrt(3)i,x=-2sqrt(3)i