What are the solutions to the equation 16x^2+36=-48x ?

The solutions to the equation 16x^2+36=-48x are x=-3/2

Find the zeros of 16x^2+36=-48x

The zeros of 16x^2+36=-48x are x=-3/2

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16 x^{2} + 36 = - 48 x

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

16 x^{2} + 36 = - 48 x

Move

48 x

to the left side

16 x^{2} + 36 + 48 x = 0

Write in the standard form

a x^{2} + b x + c = 0

16 x^{2} + 48 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 16 \cdot 36}{2 \cdot 16}

4 8^{2} - 4 \cdot 16 \cdot 36 = 0

x_{1, 2} = \frac{- 48 \pm 0}{2 \cdot 16}

x = \frac{- 48}{2 \cdot 16}

\frac{- 48}{2 \cdot 16} = - \frac{3}{2}

x = - \frac{3}{2}

The solution to the quadratic equation is:

x = - \frac{3}{2}

36 π = 4 π r^{2}

2 x^{2} - 8 x = 0

p, q = 400 - p^{2}

y = - \frac{1}{20} y^{2}

124 = 0.006 a^{2} - 0.02 a + 120

What are the solutions to the equation 16x^2+36=-48x ?
The solutions to the equation 16x^2+36=-48x are x=-3/2
Find the zeros of 16x^2+36=-48x
The zeros of 16x^2+36=-48x are x=-3/2