What are the solutions to the equation completesquare x^2-10x-4=0 ?

The solutions to the equation completesquare x^2-10x-4=0 are x=sqrt(29)+5,x=-sqrt(29)+5

Find the zeros of completesquare x^2-10x-4=0

The zeros of completesquare x^2-10x-4=0 are x=sqrt(29)+5,x=-sqrt(29)+5

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x^{2} - 10 x - 4 = 0

x = 29 + 5, x = - 29 + 5

Decimal Notation

x = 10.38516 \dots, x = - 0.38516 \dots

Solution steps

x^{2} - 10 x - 4 = 0

Move

4

to the right side

x^{2} - 10 x = 4

Rewrite in the form

(x + a)^{2} = b

(x - 5)^{2} = 29

For

the solutions are

f (x) = a, - a

Solve

x - 5 = 29 : x = 29 + 5

Solve

x - 5 = - 29 : x = - 29 + 5

The solutions to the quadratic equation are:

x = 29 + 5, x = - 29 + 5

y, x^{2} + 14 x y + 49 y^{2} = 100

x, z = x^{2} - x e^{y}

n, 2 n^{2} + 4 n = 0

x^{2} + 4 x + 10 = 6

p^{2} - 3 p = 0

What are the solutions to the equation completesquare x^2-10x-4=0 ?
The solutions to the equation completesquare x^2-10x-4=0 are x=sqrt(29)+5,x=-sqrt(29)+5
Find the zeros of completesquare x^2-10x-4=0
The zeros of completesquare x^2-10x-4=0 are x=sqrt(29)+5,x=-sqrt(29)+5